A drive in theater charges $3.50 per car, the drive in already admitted 100 cars, solve an inequality to find the number of cars the drive in needs to admit to make atleast 500$

They need to admit 43 more cars to make at least $500 Solution:Given, A drive in theater charges $3.50 per car,  The drive in already admitted 100 cars,  Then, money collected until now is $ 3.50 x 100 = $ 350  We have to solve an inequality to find the number of cars the drive in needs to admit to make atleast 500$ Now, let the number of cars need to be admitted be "n"Then, inequality is:collected amount + needed amount ≥ $ 500  $ 350 + $ 3.50 x n ≥ $ 500 350 + 3.5n ≥ 500 3.5n ≥ 500 – 350  On solving, we get3.5n ≥ 150  n ≥ 42.857 As number of cars can’t be fractions, n = 43 Hence, they need to admit 43 more cars to make at least $500